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reverseproxy: Optimize base case for least_conn and random_choose policies (#5487)
When only a single request has the least amount of requests, there's no need to compute a random number, because the modulo of 1 will always be 0 anyways.
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1 changed files with 4 additions and 1 deletions
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@ -187,7 +187,7 @@ func (LeastConnSelection) Select(pool UpstreamPool, _ *http.Request, _ http.Resp
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// sample: https://en.wikipedia.org/wiki/Reservoir_sampling
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if numReqs == leastReqs {
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count++
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if (weakrand.Int() % count) == 0 { //nolint:gosec
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if count > 1 || (weakrand.Int()%count) == 0 { //nolint:gosec
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bestHost = host
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}
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}
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@ -707,6 +707,9 @@ func leastRequests(upstreams []*Upstream) *Upstream {
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if len(best) == 0 {
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return nil
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}
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if len(best) == 1 {
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return best[0]
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}
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return best[weakrand.Intn(len(best))] //nolint:gosec
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}
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